x=3+((x^2)-9)^1/2

Solution for x=3+((x^2)-9)^1/2 equation:

x in (-oo:+oo)

x = ((x^2-9)^1)/2+3 // - ((x^2-9)^1)/2+3

x-(((x^2-9)^1)/2)-3 = 0

x-((x^2-9)/2)-3 = 0

(-1*(x^2-9))/2+x-3 = 0

(-1*(x^2-9))/2+(2*x)/2+(-3*2)/2 = 0

2*x-1*(x^2-9)-3*2 = 0

2*x-x^2-6+9 = 0

2*x-x^2+3 = 0

2*x-x^2+3 = 0

2*x-x^2+3 = 0

DELTA = 2^2-(-1*3*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)-2)/(-1*2) or x = (-16^(1/2)-2)/(-1*2)

x = -1 or x = 3

(x+1)*(x-3) = 0

((x+1)*(x-3))/2 = 0

((x+1)*(x-3))/2 = 0 // * 2

(x+1)*(x-3) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x-3 )

x-3 = 0 // + 3

x = 3

x in { -1, 3 }